Rev 25118 | Blame | Compare with Previous | Last modification | View Log | Download | RSS feed
\name{birthday}\alias{qbirthday}\alias{pbirthday}\title{Probability of coincidences}\description{Computes approximate answers to a generalised \dQuote{birthday paradox}problem. \code{pbirthday} computes the probability of a coincidenceand \code{qbirthday} computes the number of observations needed tohave a specified probability of coincidence.}\usage{qbirthday(prob = 0.5, classes = 365, coincident = 2)pbirthday(n, classes = 365, coincident = 2)}\arguments{\item{classes}{How many distinct categories the people could fall into}\item{prob}{The desired probability of coincidence}\item{n}{The number of people}\item{coincident}{The number of people to fall in the same category}}\value{\item{qbirthday}{Number of people needed for a probability \code{prob} that \code{k} ofthem have the same one out of \code{classes} equiprobable labels.}\item{pbirthday}{Probability of the specified coincidence}}\details{The birthday paradox is that a very small number of people, 23,suffices to have a 50-50 chance that two of them have the samebirthday. This function generalises the calculation to probabilitiesother than 0.5, numbers of coincident events other than 2, and numbersof classes other than 365.This formula is approximate, as the example below shows. For\code{coincident=2} the exact computation is straightforward and may bepreferable.}\references{Diaconis P, Mosteller F., \dQuote{Methods for studying coincidences}.JASA 84:853-861}\examples{## the standard versionqbirthday()## same 4-digit PIN numberqbirthday(classes=10^4)## 0.9 probability of three coincident birthdaysqbirthday(coincident=3,prob=0.9)## Chance of 4 coincident birthdays in 150 peoplepbirthday(150,coincident=4)## Accuracy compared to exact calculationx1<- sapply(10:100, pbirthday)x2<-1-sapply(10:100, function(n)prod((365:(365-n+1))/rep(365,n)))par(mfrow=c(2,2))plot(x1,x2,xlab="approximate",ylab="exact")abline(0,1)plot(x1,x1-x2,xlab="approximate",ylab="error")abline(h=0)plot(x1,x2,log="xy",xlab="approximate",ylab="exact")abline(0,1)plot(1-x1,1-x2,log="xy",xlab="approximate",ylab="exact")abline(0,1)}\keyword{distribution}