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\name{lsfit}\title{Find the Least Squares Fit}\usage{lsfit(x, y, wt, intercept=TRUE, tolerance=1e-07, yname=NULL)}\alias{lsfit}\arguments{\item{x}{a matrix whose rows correspond to cases and whose columnscorrespond to variables.}\item{y}{the responses, possibly matrix valued if you want to fit multipleleft hand sides.}\item{wt}{an optional vector of weights for performing weighted least squares.}\item{intercept}{whether or not an intercept term should be used.}\item{tolerance}{the tolerance to be used in the matrix decomposition.}\item{yname}{an unused parameter for compatibility.}}\description{The least squares estimate of \bold{\eqn{\beta}{b}} in the model\deqn{\bold{Y} = \bold{X \beta} + \bold{\epsilon}}{y = X b + e}is found.}\details{If weights are specified then a weighted least squares is performedwith the weight given to the \emph{j}th case specified by the \emph{j}thentry in \code{wt}.If any observation has a missing value in any field, that observationis removed before the analysis is carried out.This can be quite inefficient if there is a lot of missing data.The implementation is via a modification of the LINPACK subroutineswhich allow for multiple left-hand sides.}\value{A list with the following named components:\item{coef}{the least squares estimates of the coefficients inthe model (stated below).}\item{residuals}{residuals from the fit.}\item{intercept}{indicates whether an intercept was fitted.}\item{qr}{the QR decomposition of the design matrix.}}\seealso{\code{\link{lm}} which usually is preferable;\code{\link{ls.print}}, \code{\link{ls.diag}}.}\examples{\testonly{example("lm", echo = FALSE)}##-- Using the same data as the lm(.) example:lsD9 <- lsfit(x = codes(gl(2,10)), y = weight)ls.print(lsD9)}\keyword{regression}