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R version 2.15.0 (2012-03-30)Copyright (C) 2012 The R Foundation for Statistical ComputingISBN 3-900051-07-0Platform: x86_64-unknown-linux-gnu (64-bit)R is free software and comes with ABSOLUTELY NO WARRANTY.You are welcome to redistribute it under certain conditions.Type 'license()' or 'licence()' for distribution details.R is a collaborative project with many contributors.Type 'contributors()' for more information and'citation()' on how to cite R or R packages in publications.Type 'demo()' for some demos, 'help()' for on-line help, or'help.start()' for an HTML browser interface to help.Type 'q()' to quit R.> #> # Test out the "return.all" argument of xpred> # this is a very small test case for debugging> #> library(rpart)>> tdata <- data.frame(y=1:12, x1= 12:1, x2=c(1,1,5,5,4,4,9,9,7,7,3,3))> xgrp <- rep(1:3, length=12)>> fit1 <- rpart(y ~ x1 + x2, tdata, minsplit=6)> xfit1 <- xpred.rpart(fit1, xval=xgrp, return.all=T)>> xfit2 <- array(0, dim=dim(xfit1))> cplist <- as.numeric(dimnames(xfit1)[[2]])>> for (i in 1:3) {+ tfit <- rpart(y ~ x1+x2, tdata, subset=(xgrp !=i), minsplit=6)+ # xvals are actually done on the absolute risk (node's risk /n), not on+ # the rescaled risk ((node risk)/ (top node risk)) which is the basis+ # for the printed CP. To get the right answer we need to rescale.+ cp2 <- cplist * (fit1$frame$dev[1] / fit1$frame$n[1]) /+ (tfit$frame$dev[1] / tfit$frame$n[1])++ for (j in 1:length(cp2)) {+ tfit2 <- prune(tfit, cp=cp2[j])+ temp <- predict(tfit2, newdata=tdata[xgrp==i,], type='matrix')+ xfit2[xgrp==i, j] <- temp+ }+ }>> all.equal(xfit1, xfit2, check.attributes=FALSE)[1] TRUE>> proc.time()user system elapsed0.264 0.070 0.367